persamaan garis lurus melalui titik (2,4) dan (-3,-6) adalah
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Persamaan garis lurus (PGL)
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[tex] \frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1} \\ \\ \frac{y - 4}{ - 6 - 4} = \frac{x - 2}{ - 3 - 2} \\ \\ \frac{y - 4}{ - 10} = \frac{x - 2}{ - 5} [/tex]
-10(x - 2) = -5(y - 4)
-10x + 20 = -5y + 20
5y = 10x - 20 + 20
5y = 10x
________÷5
y = 2x
[answer.2.content]
